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⚛️ Physics  ·  Semiconductor Electronics  ·  NEET & JEE

An LED emits light of wavelength 620 nm. The band gap of the semiconductor used is about (take hc = 1240 eV·nm):

Answer: 2.0 eV.

  • A 1.1 eV
  • B 1.4 eV
  • C 3.0 eV
  • D 2.0 eV

Correct answer: D. 2.0 eV

Explanation: E<sub>g</sub> = hc/&lambda; = 1240/620 = 2.0 eV, the energy of the emitted photon.

Conductorconduction bandvalence bandbands overlapSemiconductorconduction bandvalence bandsmall gap (~1 eV)Insulatorconduction bandvalence bandlarge gap(> 3 eV)

Conductors have overlapping bands, semiconductors have a small energy gap that can be bridged by heat or doping, and insulators have a large gap that blocks conduction.

Concept context

Band theory, p-n junction, diodes, transistors, logic gates, and integrated circuits.

Read the full Semiconductor Electronics notes →