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⚛️ Physics  ·  Motion in a Plane  ·  NEET & JEE

The horizontal range of a projectile is maximum for a launch angle of:

Answer: 45°.

  • A 45°
  • B 30°
  • C 60°
  • D 90°

Correct answer: A. 45°

Explanation: Range R = u²sin2θ/g is greatest when sin2θ = 1, i.e. θ = 45°.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

Read the full Motion in a Plane notes →