⚛️ Physics · Motion in a Plane · NEET & JEE

For a projectile, the maximum height equals the horizontal range. The angle of projection satisfies:

Answer: tanθ = 4.

A tanθ = 4
B tanθ = 1
C tanθ = 2
D θ = 45°

Correct answer: A. tanθ = 4

Explanation: R = H → u²sin2θ/g = u²sin²θ/2g → 4cosθ = sinθ → tanθ = 4.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

Read the full Motion in a Plane notes →

For a projectile, the maximum height equals the horizontal range. The angle of projection satisfies:

Concept context

More Motion in a Plane questions