⚛️ Physics · Motion in a Plane · NEET & JEE

A projectile is launched at 45° with speed 20 m/s. Its horizontal range is (g=10 m/s²):

Answer: 40 m.

A 20 m
B 40 m
C 60 m
D 80 m

Correct answer: B. 40 m

Explanation: R = u²sin(2θ)/g = 400×sin90°/10 = 400/10 = 40 m.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A projectile is launched at 45° with speed 20 m/s. Its horizontal range is (g=10 m/s²):

Concept context

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