Answer: 45°.
- A 30°
- B 45°
- C 60°
- D 90°
Correct answer: B. 45°
Explanation: Range R = u²sin(2θ)/g. Maximum when sin(2θ)=1, i.e., 2θ=90°, θ=45°.
Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.
Concept context
Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.