⚛️ Physics · Motion in a Plane · NEET & JEE

A particle moves with initial velocity 5 m/s and constant acceleration 2 m/s². How far does it travel in the 4th second?

Answer: 13 m.

A 12 m
B 13 m
C 14 m
D 15 m

Correct answer: B. 13 m

Explanation: s<sub>n</sub> = u + a(2n-1)/2 = 5 + 2(2×4-1)/2 = 5 + 7 = 12 m.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A particle moves with initial velocity 5 m/s and constant acceleration 2 m/s². How far does it travel in the 4th second?

Concept context

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