A particle moves in a circle of radius 4 m. Its speed is 4 m s -1 and increasing at 3 m s -2 . The magnitude of its net acceleration at that instant is:

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A particle moves in a circle of radius 4 m. Its speed is 4 m s-1 and increasing at 3 m s-2. The magnitude of its net acceleration at that instant is:

Answer: 5 m s -2.

A 3 m s-2
B 4 m s-2
C 5 m s-2
D 7 m s-2

Correct answer: C. 5 m s-2

Explanation: Centripetal acceleration = v2/r = 16/4 = 4 m s-2, tangential = 3 m s-2. Net = √(42 + 32) = 5 m s-2.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A particle moves in a circle of radius 4 m. Its speed is 4 m s<sup>-1</sup> and increasing at 3 m s<sup>-2</sup>. The magnitude of its net acceleration at that instant is:

Concept context

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