⚛️ Physics · Motion in a Plane · NEET & JEE

A particle is thrown vertically with speed u. The ratio of max height to range when launched at 45° is:

Answer: 1:4.

A 1:4
B 1:2
C 1:1
D 2:1

Correct answer: A. 1:4

Explanation: H = u²/(2g); R at 45° = u²/g. H/R = 1/2. Actually ratio H:R = 1:2... wait H=u²sin²45/(2g)=u²/4g and R=u²sin90/g=u²/g so H:R = 1:4.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A particle is thrown vertically with speed u. The ratio of max height to range when launched at 45° is:

Concept context

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