⚛️ Physics · Motion in a Plane · NEET & JEE

A particle is projected at angle α above horizontal. Time of flight equals:

Answer: 2u·sinα/g.

A u·cosα/g
B u·sinα/g
C 2u·sinα/g
D 2u·cosα/g

Correct answer: C. 2u·sinα/g

Explanation: Time of flight T = 2u·sinα/g (time up = time down, each = u·sinα/g).

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A particle is projected at angle α above horizontal. Time of flight equals:

Concept context

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