⚛️ Physics · Motion in a Plane · NEET & JEE

A particle in uniform circular motion at speed 10 m/s turns through a quarter circle. The magnitude of its change in velocity is:

Answer: 14.1 m/s.

A 10 m/s
B 14.1 m/s
C 20 m/s
D 0 m/s

Correct answer: B. 14.1 m/s

Explanation: Velocity vectors are perpendicular, so |Δv| = √(10² + 10²) = 10√2 ≈ 14.1 m/s.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A particle in uniform circular motion at speed 10 m/s turns through a quarter circle. The magnitude of its change in velocity is:

Concept context

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