⚛️ Physics · Motion in a Plane · NEET & JEE

A particle has displacement x = A·sin(ωt). Its maximum velocity is:

Answer: Aω.

A A/ω
B Aω
C A/ω²
D Aω²

Correct answer: B. Aω

Explanation: v = dx/dt = Aω·cos(ωt). Maximum when cos=1: vmax = Aω.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A particle has displacement x = A·sin(ωt). Its maximum velocity is:

Concept context

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