⚛️ Physics · Motion in a Plane · NEET & JEE

A body moving at 10 m/s is brought to rest by a constant force. If deceleration is 2 m/s², the time taken is:

Answer: 5 s.

A 2 s
B 5 s
C 10 s
D 20 s

Correct answer: B. 5 s

Explanation: v = u + at → 0 = 10 + (-2)t → t = 5 s.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A body moving at 10 m/s is brought to rest by a constant force. If deceleration is 2 m/s², the time taken is:

Concept context

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