⚛️ Physics · Motion in a Plane · NEET & JEE

A ball is thrown from a building 80 m high with horizontal speed 10 m/s. Horizontal range when it hits ground is (g=10):

Answer: 40 m.

A 30 m
B 40 m
C 50 m
D 60 m

Correct answer: B. 40 m

Explanation: t = √(2h/g) = √(160/10) = √16 = 4 s. Range = v×t = 10×4 = 40 m.

Projectile trajectories launched at 15, 30, 45, 60, 75 and 90 degrees at the same speed, each annotated with range R, maximum height H and time of flight T, with coloured dots marking equal time intervals

Projectiles at equal speed: range is maximum at 45°, and complementary angles (30° and 60°) share the same range. Image: Cmglee, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Vectors, projectile motion, uniform circular motion, and relative velocity - the foundation of 2D kinematics for NEET and JEE.

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A ball is thrown from a building 80 m high with horizontal speed 10 m/s. Horizontal range when it hits ground is (g=10):

Concept context

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