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⚛️ Physics  ·  Mechanical Properties of Solids  ·  NEET & JEE

A rubber cord has a cross-sectional area 1 mm² and total unstretched length 10 cm. It is stretched to 12 cm. If Youngs modulus of rubber is 5 × 10⁸ Pa, the tension in the cord is:

Answer: 100 N.

  • A 50 N
  • B 100 N
  • C 10 N
  • D 150 N

Correct answer: B. 100 N

Explanation: Strain = 2/10 = 0.2. Stress = Y × strain = 5×10⁸ × 0.2 = 1×10⁸ Pa. Force = stress × area = 1×10⁸ Pa × 1×10⁻⁶ m² = 100 N.

Stress-Strain Curve for a Ductile Metal WireStrainStresselastic limityield pointUTS (max stress)fractureSlope of the straight (elastic) portion = Young's modulus Y; the curve beyond elastic limit shows permanent (plastic) deformation

A typical stress-strain curve: the initial straight line (Hooke's Law region, slope = Young's modulus) ends at the elastic limit; beyond the yield point, deformation becomes permanent, peaking at the ultimate tensile strength before the wire finally fractures.

Concept context

Stress, strain, Hookes law, and the elastic moduli that describe how solids deform and recover under load.

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