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⚛️ Physics  ·  Mechanical Properties of Solids  ·  NEET & JEE

A rod fixed between two rigid walls is heated so that it would expand by ΔL if free, but the walls prevent any expansion. If Youngs modulus is Y, area A, and coefficient of linear expansion is α, the thermal stress (compressive force per area) developed is:

Answer: Y·α·ΔT.

  • A Y·α·ΔT
  • B Y·α·ΔT/A
  • C Y·α·ΔT×A
  • D α·ΔT/Y

Correct answer: A. Y·α·ΔT

Explanation: Since the rod cannot expand, the strain equivalent is α·ΔT (the strain it would have had if free), so thermal stress = Y × (α·ΔT).

Stress-Strain Curve for a Ductile Metal WireStrainStresselastic limityield pointUTS (max stress)fractureSlope of the straight (elastic) portion = Young's modulus Y; the curve beyond elastic limit shows permanent (plastic) deformation

A typical stress-strain curve: the initial straight line (Hooke's Law region, slope = Young's modulus) ends at the elastic limit; beyond the yield point, deformation becomes permanent, peaking at the ultimate tensile strength before the wire finally fractures.

Concept context

Stress, strain, Hookes law, and the elastic moduli that describe how solids deform and recover under load.

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