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⚛️ Physics  ·  Mechanical Properties of Fluids  ·  NEET & JEE

Two soap bubbles of radii r<sub>1</sub> and r<sub>2</sub> are connected by a tube. If r<sub>1</sub> > r<sub>2</sub>, what happens?

Answer: Smaller bubble (r 2 ) shrinks and larger (r 1 ) grows.

  • A Smaller bubble (r<sub>2</sub>) shrinks and larger (r<sub>1</sub>) grows
  • B The larger bubble shrinks while the smaller one grows instead
  • C Both bubbles settle to exactly the same final equilibrium radius
  • D Neither bubble's size changes once they are connected by the tube

Correct answer: A. Smaller bubble (r<sub>2</sub>) shrinks and larger (r<sub>1</sub>) grows

Explanation: Excess pressure in a soap bubble = 4T/r. The smaller bubble (r<sub>2</sub>) has higher pressure than the larger one (r<sub>1</sub>). Air flows from smaller to larger. The smaller bubble shrinks.

Continuity Equation: Narrow Pipe → Faster FlowA₁, v₁ (wide, slow)A₂, v₂ (narrow, fast)A₁v₁ = A₂v₂ (continuity)Smaller area → higher speed → (by Bernoulli) LOWER pressure

Since the same volume of fluid must pass every cross-section per second (continuity), the fluid speeds up where the pipe narrows; Bernoulli's equation then says this faster-moving fluid has lower pressure - the principle behind a venturi meter and an aircraft wing's lift.

Concept context

Pressure, buoyancy, Bernoulli equation, viscosity, and surface tension.

Read the full Mechanical Properties of Fluids notes →