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⚛️ Physics  ·  Mechanical Properties of Fluids  ·  NEET & JEE

A tank of large cross-section has a hole of area a at depth h. The range of the horizontal jet of water on the ground (if the hole is at height H from ground) is:

Answer: x = 2√(h(H-h)).

  • A x = 2√(h(H-h))
  • B x = √(2gH)
  • C x = √(gh)
  • D x = 2H

Correct answer: A. x = 2√(h(H-h))

Explanation: Efflux speed v = √(2gh). Time to fall height (H-h): (H-h) = ½gt², t = √(2(H-h)/g). Range x = vt = √(2gh)×√(2(H-h)/g) = 2√(h(H-h)).

Continuity Equation: Narrow Pipe → Faster FlowA₁, v₁ (wide, slow)A₂, v₂ (narrow, fast)A₁v₁ = A₂v₂ (continuity)Smaller area → higher speed → (by Bernoulli) LOWER pressure

Since the same volume of fluid must pass every cross-section per second (continuity), the fluid speeds up where the pipe narrows; Bernoulli's equation then says this faster-moving fluid has lower pressure - the principle behind a venturi meter and an aircraft wing's lift.

Concept context

Pressure, buoyancy, Bernoulli equation, viscosity, and surface tension.

Read the full Mechanical Properties of Fluids notes →