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⚛️ Physics  ·  Mechanical Properties of Fluids  ·  NEET & JEE

A siphon transfers liquid from a container to a lower level. The maximum height h the siphon can reach above the container level is:

Answer: h = P atm /(ρg) ≈ 10.3 m for water.

  • A h = P<sub>atm</sub>/(ρg) ≈ 10.3 m for water
  • B h = ∞, since a siphon can theoretically rise to any height
  • C h = 5 m, a fixed value independent of atmospheric pressure
  • D h = 1 m, a fixed value independent of fluid density or pressure

Correct answer: A. h = P<sub>atm</sub>/(ρg) ≈ 10.3 m for water

Explanation: The siphon works as long as pressure at the top does not go below zero (vacuum). Maximum height: P<sub>atm</sub> - ρgh = 0 → h = P<sub>atm</sub>/(ρg) = 10⁵/(1000×10) = 10 m for water.

Continuity Equation: Narrow Pipe → Faster FlowA₁, v₁ (wide, slow)A₂, v₂ (narrow, fast)A₁v₁ = A₂v₂ (continuity)Smaller area → higher speed → (by Bernoulli) LOWER pressure

Since the same volume of fluid must pass every cross-section per second (continuity), the fluid speeds up where the pipe narrows; Bernoulli's equation then says this faster-moving fluid has lower pressure - the principle behind a venturi meter and an aircraft wing's lift.

Concept context

Pressure, buoyancy, Bernoulli equation, viscosity, and surface tension.

Read the full Mechanical Properties of Fluids notes →