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⚛️ Physics  ·  Kinetic Theory  ·  NEET & JEE

Mean free path of a gas molecule is found to be λ at pressure P and temperature T. If the pressure is doubled at constant temperature, the new mean free path becomes:

Answer: λ/2.

  • A
  • B λ/2
  • C
  • D λ

Correct answer: B. λ/2

Explanation: At constant T, doubling pressure doubles the number density n (since PV=nRT, n=P/kT at fixed T). Since λ ∝ 1/n, the mean free path becomes λ/2.

Maxwell-Boltzmann Speed Distributionspeed (v)fraction of moleculesv_pv_avgv_rmsv_p < v_avg < v_rms always, for any gas at any temperature

Not all gas molecules move at the same speed - the Maxwell-Boltzmann distribution shows the spread, with the most probable speed vp slightly less than the average vavg, which is slightly less than the root-mean-square speed vrms used in the pressure formula.

Concept context

Kinetic theory of gases connects molecular motion to pressure and temperature, explaining gas laws, specific heats, and molecular speeds.

Read the full Kinetic Theory notes →