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⚛️ Physics  ·  Kinetic Theory  ·  NEET & JEE

For a gas mixture of monatomic and diatomic molecules with degrees of freedom f<sub>1</sub> and f<sub>2</sub> respectively in equal number of moles, the average degrees of freedom of the mixture is:

Answer: (f 1 +f 2 )/2.

  • A f<sub>1</sub> + f<sub>2</sub>
  • B (f<sub>1</sub>+f<sub>2</sub>)/2
  • C f<sub>1</sub> × f<sub>2</sub>
  • D (f<sub>1</sub> - f<sub>2</sub>)/2

Correct answer: B. (f<sub>1</sub>+f<sub>2</sub>)/2

Explanation: For an equimolar mixture, the average degrees of freedom is the simple average of the individual values: (f<sub>1</sub>+f<sub>2</sub>)/2.

Maxwell-Boltzmann Speed Distributionspeed (v)fraction of moleculesv_pv_avgv_rmsv_p < v_avg < v_rms always, for any gas at any temperature

Not all gas molecules move at the same speed - the Maxwell-Boltzmann distribution shows the spread, with the most probable speed vp slightly less than the average vavg, which is slightly less than the root-mean-square speed vrms used in the pressure formula.

Concept context

Kinetic theory of gases connects molecular motion to pressure and temperature, explaining gas laws, specific heats, and molecular speeds.

Read the full Kinetic Theory notes →