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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

Two satellites orbit at 2R and 3R from Earth center. Period ratio T<sub>1</sub>:T<sub>2</sub>:

Answer: 2*sqrt(2):3*sqrt(3).

  • A 2:3, treating the period as directly proportional to radius
  • B 4:9, treating the period as proportional to the square of radius
  • C 2*sqrt(2):3*sqrt(3)
  • D 8:27, treating the period as proportional to the cube of radius

Correct answer: C. 2*sqrt(2):3*sqrt(3)

Explanation: T proportional to r<sup>3/2</sup>. T<sub>1</sub>:T<sub>2</sub> = (2R)<sup>3/2</sup> : (3R)<sup>3/2</sup> = 2*sqrt(2) : 3*sqrt(3).

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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