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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

Relation between escape velocity (ve) and orbital velocity (vo) at Earth's surface:

Answer: ve = sqrt(2) x vo.

  • A ve = vo
  • B ve = 2vo
  • C ve = sqrt(2) x vo
  • D vo = sqrt(2) x ve

Correct answer: C. ve = sqrt(2) x vo

Explanation: vo = sqrt(gR), ve = sqrt(2gR) = sqrt(2) x vo. Escape velocity is sqrt(2) times orbital velocity.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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