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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

Ratio of orbital velocity to escape velocity at Earth's surface:

Answer: 1/sqrt(2).

  • A 1/2
  • B 1/sqrt(2)
  • C sqrt(2)
  • D 2

Correct answer: B. 1/sqrt(2)

Explanation: vo = sqrt(gR), ve = sqrt(2gR). Ratio vo/ve = sqrt(gR)/sqrt(2gR) = 1/sqrt(2).

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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