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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

If mass of Earth doubled but radius stayed same, escape velocity would:

Answer: Increase by sqrt(2).

  • A Halve under typical conditions
  • B Stay same according to standard textbooks
  • C Increase by sqrt(2)
  • D Double in general practice

Correct answer: C. Increase by sqrt(2)

Explanation: ve = sqrt(2GM/R). If M doubles, ve = sqrt(2 x 2GM/R) = sqrt(2) x original ve.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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