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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

Gravitational PE of a mass m at height h above Earth's surface (for h << R) is:

Answer: mgh.

  • A mgh
  • B mg/h
  • C mh/g
  • D -mgh

Correct answer: A. mgh

Explanation: Near Earth's surface, gravitational PE = mgh (taking surface as reference, PE is positive above it).

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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