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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

At a height equal to the Earth radius above the surface, the acceleration due to gravity becomes:

Answer: g/4.

  • A g/2
  • B g/4
  • C g/9
  • D g

Correct answer: B. g/4

Explanation: g' = g R²/(R + h)² = g R²/(2R)² = g/4.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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