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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

At a distance r from the centre inside a uniform solid sphere of radius R (r < R), the gravitational field is proportional to:

Answer: r.

  • A 1/r<sup>2</sup>
  • B 1/r
  • C r
  • D r<sup>2</sup>

Correct answer: C. r

Explanation: Only the mass within radius r acts, and that mass ∝ r<sup>3</sup>, so g = GM(r)/r<sup>2</sup> ∝ r<sup>3</sup>/r<sup>2</sup> = r. The field grows linearly with r inside.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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