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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

A satellite in orbit has KE = K. Its total energy is:

Answer: -K.

  • A -K/2
  • B -K
  • C K
  • D 2K

Correct answer: B. -K

Explanation: For circular orbit: KE = GMm/(2r) = K. PE = -GMm/r = -2K. Total = KE + PE = K - 2K = -K.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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