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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

A planet has mass 2M and radius 2R. Surface gravity compared to Earth:

Answer: Half.

  • A Same
  • B Half
  • C Double
  • D One-fourth

Correct answer: B. Half

Explanation: g' = G(2M)/(2R)<sup>2</sup> = 2GM/4R<sup>2</sup> = GM/(2R<sup>2</sup>) = g/2. Surface gravity is half of Earth.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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