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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

A body is projected vertically upward from Earth's surface with speed ve/2 (ve = escape speed). Max height reached:

Answer: R/3.

  • A R/3
  • B R/2
  • C R
  • D 2R

Correct answer: A. R/3

Explanation: Energy: (1/2)m(ve/2)<sup>2</sup> - GMm/R = -GMm/(R+h). (ve<sup>2</sup>/8) - GM/R = -GM/(R+h). ve<sup>2</sup> = 2gR = 2GM/R. GM/(4R) - GM/R = -GM/(R+h). -3GM/(4R) = -GM/(R+h). R+h = 4R/3. h = R/3.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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