Answer: 6 × 10¹⁴ Hz.
- A 6 × 10¹⁴ Hz
- B 6 × 10⁸ Hz
- C 5 × 10⁶ Hz
- D 3 × 10⁸ Hz
Correct answer: A. 6 × 10¹⁴ Hz
Explanation: f = c/λ = (3×10⁸)/(500×10⁻⁹) = 3×10⁸/5×10⁻⁷ = 6×10¹⁴ Hz. Visible light is in the range 4-7.5 × 10¹⁴ Hz.
In an electromagnetic wave, the oscillating electric field (E) and magnetic field (B) are perpendicular to each other and to the direction the wave travels - a purely transverse wave that needs no medium, unlike sound.
Concept context
Maxwell's equations, EM spectrum, properties, and applications of each band.