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⚛️ Physics  ·  Electromagnetic Waves  ·  NEET & JEE

The energy density of an EM wave has equal contributions from E and B fields:

Answer: u = ε_0 E² = B²/μ_0 (each term equal at any instant).

  • A u = ε_0 E² = B²/μ_0 (each term equal at any instant)
  • B u = ε_0 E² mainly, ignoring the magnetic field's contribution largely
  • C u = B²/μ_0 mainly, ignoring the electric field's contribution largely
  • D u = E² + B², adding the fields without their respective constants

Correct answer: A. u = ε_0 E² = B²/μ_0 (each term equal at any instant)

Explanation: Total energy density u = ½ε_0 E² + ½B²/μ_0. At any instant, ½ε_0 E² = ½B²/μ_0 (equal electric and magnetic energy densities). Total u = ε_0 E² = B²/μ_0.

Electromagnetic Wave: E ⊥ B ⊥ Direction of TravelpropagationE (electric field, vertical plane)B (magnetic field, horizontal plane, perpendicular to E)

In an electromagnetic wave, the oscillating electric field (E) and magnetic field (B) are perpendicular to each other and to the direction the wave travels - a purely transverse wave that needs no medium, unlike sound.

Concept context

Maxwell's equations, EM spectrum, properties, and applications of each band.

Read the full Electromagnetic Waves notes →