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⚛️ Physics  ·  Electromagnetic Waves  ·  NEET & JEE

The average energy density of an EM wave is related to the electric field by:

Answer: = ε_0 E 0 ²/2 = ε_0 E rms ².

  • A <u> = ε_0 E<sub>0</sub>²/2 = ε_0 E<sub>rms</sub>²
  • B <u> = ε_0 E<sub>0</sub>² in most textbook accounts
  • C <u> = ε_0 E<sub>0</sub>²/4 during normal conditions
  • D <u> = 2ε_0 E<sub>0</sub>² as generally observed

Correct answer: A. <u> = ε_0 E<sub>0</sub>²/2 = ε_0 E<sub>rms</sub>²

Explanation: Instantaneous u = ε_0 E² (total, including both E and B contributions). Time-averaged: <u> = ε_0 E<sub>rms</sub>² = ε_0 E<sub>0</sub>²/2. Intensity = <u> × c = ε_0 c E<sub>0</sub>²/2.

Electromagnetic Wave: E ⊥ B ⊥ Direction of TravelpropagationE (electric field, vertical plane)B (magnetic field, horizontal plane, perpendicular to E)

In an electromagnetic wave, the oscillating electric field (E) and magnetic field (B) are perpendicular to each other and to the direction the wave travels - a purely transverse wave that needs no medium, unlike sound.

Concept context

Maxwell's equations, EM spectrum, properties, and applications of each band.

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