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⚛️ Physics  ·  Electromagnetic Waves  ·  NEET & JEE

The amplitude of the E field in sunlight (I = 1000 W/m²) is:

Answer: 868 V/m.

  • A 868 V/m
  • B 1000 V/m
  • C 3 × 10⁸ V/m
  • D 30 V/m

Correct answer: A. 868 V/m

Explanation: I = ½cε_0 E<sub>0</sub>². E<sub>0</sub> = √(2I/(cε_0)) = √(2×1000/(3×10⁸×8.85×10⁻¹²)) = √(2000/2.65×10⁻³) = √(7.54×10⁵) ≈ 868 V/m.

Electromagnetic Wave: E ⊥ B ⊥ Direction of TravelpropagationE (electric field, vertical plane)B (magnetic field, horizontal plane, perpendicular to E)

In an electromagnetic wave, the oscillating electric field (E) and magnetic field (B) are perpendicular to each other and to the direction the wave travels - a purely transverse wave that needs no medium, unlike sound.

Concept context

Maxwell's equations, EM spectrum, properties, and applications of each band.

Read the full Electromagnetic Waves notes →