For the same sunlight of intensity 1.4 10 3 W/m 2 on a perfectly reflecting surface, the radiation pressure is:

⚛️ Physics · Electromagnetic Waves · NEET & JEE

For the same sunlight of intensity 1.4 × 103 W/m2 on a perfectly reflecting surface, the radiation pressure is:

Answer: 9.3 10 -6 Pa.

A 2.3 × 10-6 Pa
B 4.7 × 10-6 Pa
C 1.4 × 10-5 Pa
D 9.3 × 10-6 Pa

Correct answer: D. 9.3 × 10-6 Pa

Explanation: A perfect reflector reverses the momentum, doubling the pressure: P = 2I/c = 2 × 4.7 × 10-6 ≈ 9.3 × 10-6 Pa.

In an electromagnetic wave, the oscillating electric field (E) and magnetic field (B) are perpendicular to each other and to the direction the wave travels - a purely transverse wave that needs no medium, unlike sound.

Concept context

Maxwell's equations, EM spectrum, properties, and applications of each band.

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For the same sunlight of intensity 1.4 &times; 10<sup>3</sup> W/m<sup>2</sup> on a perfectly reflecting surface, the radiation pressure is:

Concept context

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For the same sunlight of intensity 1.4 × 10<sup>3</sup> W/m<sup>2</sup> on a perfectly reflecting surface, the radiation pressure is: