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⚛️ Physics  ·  Electromagnetic Waves  ·  NEET & JEE

A gamma-ray photon of wavelength 1 pm has energy approximately:

Answer: 1.24 MeV.

  • A 1.24 MeV
  • B 1.24 eV
  • C 1240 keV
  • D 0.124 MeV

Correct answer: A. 1.24 MeV

Explanation: E = hf = hc/λ = (6.63×10⁻³⁴ × 3×10⁸)/(10⁻¹²) = 1.99×10⁻¹³ J = 1.99×10⁻¹³/1.6×10⁻¹⁹ eV ≈ 1.24×10⁶ eV = 1.24 MeV.

Electromagnetic Wave: E ⊥ B ⊥ Direction of TravelpropagationE (electric field, vertical plane)B (magnetic field, horizontal plane, perpendicular to E)

In an electromagnetic wave, the oscillating electric field (E) and magnetic field (B) are perpendicular to each other and to the direction the wave travels - a purely transverse wave that needs no medium, unlike sound.

Concept context

Maxwell's equations, EM spectrum, properties, and applications of each band.

Read the full Electromagnetic Waves notes →