Zaymiey

⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

The skin depth δ in a conductor (where current density falls to 1/e) decreases with:

Answer: Increasing frequency.

  • A Increasing frequency
  • B Decreasing frequency
  • C Increasing resistivity
  • D No relation to frequency

Correct answer: A. Increasing frequency

Explanation: Skin depth δ = √(2ρ/μω) where ρ is resistivity and μ is permeability. At high frequency, δ decreases. This skin effect causes AC to flow near the conductor surface.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

Read the full Alternating Current notes →