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⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

An alternating current is given by i = 5 sin(100πt + π/6) A. What is the current at t = 1/600 s?

Answer: 4.33 A.

  • A 2.50 A
  • B 3.54 A
  • C 4.33 A
  • D 5.00 A

Correct answer: C. 4.33 A

Explanation: At t = 1/600 s, the phase is 100π/600 + π/6 = π/3. Therefore i = 5 sin(π/3) = 5×√3/2 = 4.33 A.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

Read the full Alternating Current notes →