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⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

The RMS value of an AC voltage with peak value V<sub>0</sub> is:

Answer: V 0 /√2.

  • A V<sub>0</sub>/√2
  • B V<sub>0</sub>/2
  • C V<sub>0</sub>√2
  • D 2V<sub>0</sub>

Correct answer: A. V<sub>0</sub>/√2

Explanation: V<sub>rms</sub> = V<sub>0</sub>/√2 ≈ 0.707 V<sub>0</sub>. For household current (230 V RMS), the peak voltage is 230 × √2 ≈ 325 V.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

Read the full Alternating Current notes →