Zaymiey

⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

The impedance Z of a series LCR circuit is:

Answer: √(R² + (X L - X C )²).

  • A √(R² + (X<sub>L</sub> - X<sub>C</sub>)²)
  • B R + X<sub>L</sub> + X<sub>C</sub>
  • C R + X<sub>L</sub> - X<sub>C</sub>
  • D √(R² + X<sub>L</sub>² + X<sub>C</sub>²)

Correct answer: A. √(R² + (X<sub>L</sub> - X<sub>C</sub>)²)

Explanation: In series LCR, X<sub>L</sub> and X<sub>C</sub> are out of phase with each other. Z = √(R² + (X<sub>L</sub> - X<sub>C</sub>)²). When X<sub>L</sub> = X<sub>C</sub>, Z = R (resonance).

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

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