The bandwidth of a resonant circuit with Q = 100 and f 0 = 1 MHz is:

⚛️ Physics · Alternating Current · NEET & JEE

The bandwidth of a resonant circuit with Q = 100 and f<sub>0</sub> = 1 MHz is:

Answer: 10 kHz.

A 10 kHz
B 100 kHz
C 1 kHz
D 100 Hz

Correct answer: A. 10 kHz

Explanation: Bandwidth Δf = f<sub>0</sub>/Q = 10⁶/100 = 10⁴ Hz = 10 kHz.

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

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The bandwidth of a resonant circuit with Q = 100 and f<sub>0</sub> = 1 MHz is:

Concept context

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