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⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

In an LC circuit, if the charge on capacitor at t=0 is Q<sub>0</sub>, the maximum current is:

Answer: Q 0 /√(LC).

  • A Q<sub>0</sub>/√(LC)
  • B Q<sub>0</sub> √(LC)
  • C Q<sub>0</sub>/LC
  • D Q<sub>0</sub> LC

Correct answer: A. Q<sub>0</sub>/√(LC)

Explanation: Energy conservation: Q<sub>0</sub>²/(2C) = (1/2)LI_max². I<sub>max</sub> = Q<sub>0</sub>/√(LC) = Q<sub>0</sub> ω_0 where ω_0 = 1/√(LC).

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

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