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⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

Average power dissipated in an AC circuit is:

Answer: V rms × I rms × cos(φ).

  • A V<sub>rms</sub> × I<sub>rms</sub> × cos(φ)
  • B V<sub>peak</sub> × I<sub>peak</sub>
  • C V<sub>rms</sub> × I<sub>rms</sub>
  • D V<sub>peak</sub> × I<sub>peak</sub> / 2

Correct answer: A. V<sub>rms</sub> × I<sub>rms</sub> × cos(φ)

Explanation: P<sub>avg</sub> = V<sub>rms</sub> × I<sub>rms</sub> × cos(φ). The factor cos(φ) is the power factor. Only the resistive component dissipates power.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

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