Zaymiey

⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

An AC circuit has R = 40 Ω and XL = 30 Ω. The apparent power is 500 VA. The real (true) power dissipated is:

Answer: 400 W.

  • A 400 W
  • B 300 W
  • C 500 W
  • D 250 W

Correct answer: A. 400 W

Explanation: Z = √(40² + 30²) = 50 Ω. Power factor = R/Z = 40/50 = 0.8. Real power = apparent power × PF = 500 × 0.8 = 400 W.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

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