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⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

A coil of 200 turns and area 0.01 m<sup>2</sup> rotates at 100 rad s<sup>-1</sup> in a uniform magnetic field of 0.4 T. What is the RMS value of the generated emf?

Answer: 56.6 V.

  • A 28.3 V
  • B 56.6 V
  • C 40.0 V
  • D 80.0 V

Correct answer: B. 56.6 V

Explanation: The peak emf is E<sub>0</sub> = NBA&omega; = 200&times;0.4&times;0.01&times;100 = 80 V. Hence E<sub>rms</sub> = E<sub>0</sub>/&radic;2 = 56.6 V.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

Read the full Alternating Current notes →