Zaymiey

⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

A 200 V, 50 Hz source drives a series RLC circuit with R=20 Ω, L=100 mH, C=10 μF. The total impedance is:

Answer: 287 Ω.

  • A √(20² + (31.4-318.3)²) Ω ≈ 287 Ω
  • B 20 Ω
  • C 100 Ω
  • D 287 Ω

Correct answer: D. 287 Ω

Explanation: X<sub>L</sub> = 2π×50×0.1 = 31.4 Ω. X<sub>C</sub> = 1/(2π×50×10⁻⁵) = 318.3 Ω. Z = √(400 + (31.4-318.3)²) = √(400 + 82369) ≈ √82769 ≈ 287.7 Ω.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

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