Zaymiey

📐 Mathematics  ·  Three Dimensional Geometry  ·  JEE

The sphere centred at (1,-1,2) passing through the origin has equation:

Answer: Both A and C are equivalent.

  • A (x-1)2+(y+1)2+(z-2)2=6
  • B x2+y2+z2=6
  • C x2+y2+z2-2x+2y-4z=0
  • D Both A and C are equivalent

Correct answer: D. Both A and C are equivalent

Explanation: Radius = sqrt(1+1+4) = sqrt(6). Equation A: (x-1)2+(y+1)2+(z-2)2=6. Expanding: x2+y2+z2-2x+2y-4z+1+1+4=6, so x2+y2+z2-2x+2y-4z=0 (equation C). Both A and C are equivalent.

zxyOP (x, y, z)

Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.

Concept context

Lines and planes in 3D space, direction cosines, distances, and angles

Read the full Three Dimensional Geometry notes →