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📐 Mathematics  ·  Three Dimensional Geometry  ·  JEE

The distance from the origin to point P(a, b, c) is:

Answer: sqrt(a 2 + b 2 + c 2 ).

  • A a + b + c
  • B sqrt(a + b + c)
  • C a<sup>2</sup> + b<sup>2</sup> + c<sup>2</sup>
  • D sqrt(a<sup>2</sup> + b<sup>2</sup> + c<sup>2</sup>)

Correct answer: D. sqrt(a<sup>2</sup> + b<sup>2</sup> + c<sup>2</sup>)

Explanation: Distance = sqrt(a<sup>2</sup> + b<sup>2</sup> + c<sup>2</sup>) using the 3D extension of the Pythagorean theorem.

zxyOP (x, y, z)

Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.

Concept context

Lines and planes in 3D space, direction cosines, distances, and angles

Read the full Three Dimensional Geometry notes →