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📐 Mathematics  ·  Three Dimensional Geometry  ·  JEE

The perpendicular distance between the parallel planes 2x+y-2z=3 and 4x+2y-4z=12 is:

Answer: 1.

  • A 1
  • B 1.5
  • C 2
  • D 3

Correct answer: A. 1

Explanation: Rewrite 4x+2y-4z=12 as 2x+y-2z=6. Distance = |d1-d2|/|n| = |3-6|/sqrt(4+1+4) = 3/3 = 1.

zxyOP (x, y, z)

Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.

Concept context

Lines and planes in 3D space, direction cosines, distances, and angles

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