Answer: x - 2y + 3z = 0.
- A x - 2y + 3z = 0
- B x + 2y + 3z = 1
- C x - 2y + 3z = 1
- D 2x - y + 3z = 0
Correct answer: A. x - 2y + 3z = 0
Explanation: Plane through origin with normal (a,b,c): ax + by + cz = 0. Here: x - 2y + 3z = 0.
Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.
Concept context
Lines and planes in 3D space, direction cosines, distances, and angles